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Add fundamental matter: masses, flavors, and decoupling

How can a massive quark disappear from the low-energy theory while leaving a measurable imprint on its strong-coupling scale? We will follow one hypermultiplet through three descriptions: its mass matrix, the central charge, and a degenerating curve. Their agreement fixes factors that dimensional analysis alone cannot determine.

The preparation is BPS masses and stability and fixed points and scaling. We work in flat four-dimensional spacetime with gauge group SU(2), not a quotient of it. The theory has N=2 supersymmetry, eight real supercharges; four are manifest in N=1 notation. The gauge rank is one. Complex hypermultiplet masses preserve all eight supercharges of the action and of a generic Coulomb vacuum.

A full fundamental hypermultiplet consists of two N=1 chirals, a column QiQ^i in the doublet and a row Q~i\widetilde Q_i in its dual. Here i=1,…,Nfi=1,\ldots,N_f labels flavors, not colors. With canonical matter kinetic terms, the relevant superpotential is

W=∑i(2 Q~iΦSWQi+miQ~iQi).(SW14.1)W=\sum_i\left(\sqrt2\,\widetilde Q_i\Phi_{\rm SW}Q^i +m_i\widetilde Q_iQ^i\right). \tag{SW14.1}

The adjoint scalar includes the gauge coupling relative to a canonical adjoint field: ΦSW=gΦcan\Phi_{\rm SW}=g\Phi_{\rm can}. The masses mim_i are fixed complex parameters of dimension one. They are not the adjoint deformation that reduced the action to N=1 in the confinement example. Equation (SW14.1) is the matter interaction in Seiberg–Witten (3.1).

Take one flavor and the classical Coulomb configuration ϕSW=acldiag⁡(1,−1)/2\phi_{\rm SW}=a_{\rm cl}\operatorname{diag}(1,-1)/2. The two color components have superpotential coefficients

M±=m±acl2,M±=∣M±∣,ucl=Tr⁡ϕSW2=acl22.(SW14.2)\mathcal M_\pm=m\pm\frac{a_{\rm cl}}{\sqrt2}, \qquad M_\pm=|\mathcal M_\pm|, \qquad u_{\rm cl}=\operatorname{Tr}\phi_{\rm SW}^2=\frac{a_{\rm cl}^2}{2}. \tag{SW14.2}

Eliminating the matter auxiliaries gives ∣M±∣2(∣Q±∣2+∣Q~±∣2)|\mathcal M_\pm|^2(|Q_\pm|^2+|\widetilde Q_\pm|^2); the two Weyl fermions have the same Dirac mass. This derives the absolute values rather than identifying a complex coefficient with a positive mass. One component becomes massless at acl=2ma_{\rm cl}=\sqrt2m, hence ucl=m2u_{\rm cl}=m^2. Quantum mechanically the special coordinate a(u)a(u) replaces the classical coordinate in the exact central charge; it is not equal to 2u\sqrt{2u} at arbitrary coupling.

Put the flavor charge in the central charge

Section titled “Put the flavor charge in the central charge”

For each flavor, choose the phase symmetry Qi↦eiαiQiQ^i\mapsto e^{i\alpha_i}Q^i, Q~i↦e−iαiQ~i\widetilde Q_i\mapsto e^{-i\alpha_i}\widetilde Q_i. Denote its charge by SiS_i. At zero masses the connected flavor Lie algebra is so(2Nf)\mathfrak{so}(2N_f): the doublet is pseudoreal, so the dual doublets can be converted to doublets with the invariant antisymmetric tensor. The resulting 2Nf2N_f chirals have a symmetric flavor pairing in the adjoint Yukawa interaction. The SiS_i select commuting rotations in this algebra. This statement does not fix the faithful global flavor group on every charged sector.

The first-paper convention used so far assigns a W boson electric charge ne=1n_e=1, so a fundamental has ne=±1/2n_e=\pm1/2. The second paper instead uses integer fundamental charges. Define its coordinates explicitly:

A=a2,B=aD,q=2ne,p=nm.(SW14.3)A=\frac a2,\qquad B=a_D,\qquad q=2n_e,\qquad p=n_m. \tag{SW14.3}

The functions a(u),aD(u)a(u),a_D(u) now belong to the theory with matter; only the earlier charge units carry over. Thus a W has q=±2q=\pm2, a fundamental has q=±1q=\pm1, and dB/dA=2 daD/dadB/dA=2\,da_D/da. This is a change of normalization, not an integral determinant-one change of the original period basis. The physical Dirac pairing becomes qp′−pq′=2(nenm′−nmne′)qp'-pq'=2(n_en_m'-n_mn_e'). Seiberg–Witten, convention note and (11.3)–(11.7)

In these coordinates the flavored charge is

Z=pB+qA+∑iSimi2,M≥2 ∣Z∣.(SW14.4)\boxed{\quad Z=pB+qA+\sum_i\frac{S_i m_i}{\sqrt2}, \qquad M\geq\sqrt2\,|Z| . \quad} \tag{SW14.4}

For the elementary states with p=0,q=±1,S=1p=0,q=\pm1,S=1, this gives 2∣Z∣=∣m±2A∣\sqrt2|Z|=|m\pm\sqrt2 A|, reproducing (SW14.2) at weak coupling. CPT reverses all charges, including SS, and preserves the mass. The flavor term and its coefficient agree with Seiberg–Witten (5.3).

Flavor weights need not all be integer in this elementary normalization; magnetically charged sectors can carry spinor weights of the flavor algebra. Neither (SW14.4) nor an allowed weight constructs a stable particle. Representation constraints and the chamber-dependent spectrum remain additional information.

For one flavor use the exact source curve

y2=F(x,u)=x2(x−u)+14mΛ13x−164Λ16.(SW14.5)y^2=F(x,u) =x^2(x-u)+\frac14m\Lambda_1^3x-\frac1{64}\Lambda_1^6 . \tag{SW14.5}

Here [x]=[u]=2[x]=[u]=2, [y]=3[y]=3, and [Λ1]=1[\Lambda_1]=1. This is input from the quantum solution, Seiberg–Witten (12.8); the checks below do not derive its nonzero quantum coefficients from symmetry alone.

A useful differential is

λ2=−24πy dxx2,∂λ2∂u=28πdxy.(SW14.6)\lambda_2=-\frac{\sqrt2}{4\pi}\frac{y\,dx}{x^2}, \qquad \frac{\partial\lambda_2}{\partial u} =\frac{\sqrt2}{8\pi}\frac{dx}{y}. \tag{SW14.6}

The second equality follows directly from 2y ∂uy=−x22y\,\partial_u y=-x^2, at fixed x,m,Λ1x,m,\Lambda_1. It has precisely the source normalization (15.2). Choose period cycles and their continuation so that A∼2u/2A\sim\sqrt{2u}/2 on the weak electric branch. As usual, this asymptotic choice and the charge dictionary are part of the specification.

Unlike the pure-theory differential, λ2\lambda_2 has mass-dependent residues. At the two points over x=0x=0, put y0=±iΛ13/8y_0=\pm i\Lambda_1^3/8 and expand y=y0+y1x+⋯y=y_0+y_1x+\cdots. The coefficient of xx in y2=Fy^2=F gives

y1=mΛ138y0=∓im,2πi Res⁡x=0λ2=∓m2.(SW14.7)y_1=\frac{m\Lambda_1^3}{8y_0}=\mp im, \qquad 2\pi i\,\operatorname{Res}_{x=0}\lambda_2 =\mp\frac m{\sqrt2}. \tag{SW14.7}

A small positively oriented loop around a pole therefore changes a period by a flavor-mass contribution. This explains why transporting cycles past poles can shift A,BA,B by constants proportional to mm. A compensating change of flavor-charge coordinates preserves ZZ; Exercise 1 makes that statement explicit. Absolute periods require this bookkeeping even though their uu-derivatives do not.

For comparison, Tachikawa’s variables X,z,ΛTX,z,\Lambda_T obey 2ΛT(X−m)/z+ΛT2z=X2−u2\Lambda_T(X-m)/z+\Lambda_T^2z=X^2-u. The explicit substitution

x=−ΛT2z,y=−iΛT2(Xz−ΛT),Λ13=−8ΛT3(SW14.8)x=-\Lambda_T^2z,\qquad y=-i\Lambda_T^2(Xz-\Lambda_T),\qquad \Lambda_1^3=-8\Lambda_T^3 \tag{SW14.8}

gives (SW14.5). Moreover X dz/zX\,dz/z, divided by 2πi22\pi i\sqrt2, equals λ2\lambda_2 plus an exact differential. Consequently aT=2Aa_T=\sqrt2 A, aD,T=2Ba_{D,T}=\sqrt2 B, and Tachikawa’s bound has no outer 2\sqrt2. The physical mass mm and modulus uu agree. The phase and factor in the curve scale are essential; the symbol Λ\Lambda alone does not specify them. Tachikawa (5.1.4), (5.2.1)–(5.2.6)

First derive the expected scale matching. In the ordinary fundamental trace normalization T(2)=1/2T(\mathbf2)=1/2, the N=1 vector and adjoint chiral contribute 3T(adj)−T(adj)=43T(\mathrm{adj})-T(\mathrm{adj})=4. Each full hyper has two fundamental chirals and subtracts one. Thus the N=2 holomorphic coefficient is

bNf=4−Nf,ΛNf bNf=E bNfexp⁡[2πiτUV(E)].(SW14.9)b_{N_f}=4-N_f,\qquad \Lambda_{N_f}^{\,b_{N_f}} =E^{\,b_{N_f}}\exp[2\pi i\tau_{\rm UV}(E)]. \tag{SW14.9}

Here τUV=θ/(2π)+4πi/g2\tau_{\rm UV}=\theta/(2\pi)+4\pi i/g^2 is the microscopic coupling; it is not the integer-charge Abelian period ratio. Holomorphy makes this running perturbatively one-loop exact. Instanton corrections to low-energy periods remain. Tachikawa (3.1.3)–(3.1.10)

Matching the coupling at a heavy threshold mm, with compatible finite scale definitions, gives Λlowb+1=mΛhighb\Lambda_{\rm low}^{b+1}=m\Lambda_{\rm high}^b. The complex mass, including its phase, occurs here; replacing it by ∣m∣|m| would lose the theta-angle information. For the curve definitions in (SW14.5), the calibrated relation is exactly

Λ04=mΛ13.(SW14.10)\Lambda_0^4=m\Lambda_1^3. \tag{SW14.10}

Now take m→∞m\to\infty, Λ13→0\Lambda_1^3\to0, holding Λ04\Lambda_0^4 fixed and keeping uu finite. Substitution, rather than dropping every term containing Λ1\Lambda_1, gives

F=x(x2−ux+Λ044)−Λ0864m2 ⟶ x(x2−ux+Λ044).(SW14.11)F=x\left(x^2-ux+\frac{\Lambda_0^4}{4}\right) -\frac{\Lambda_0^8}{64m^2} \ \longrightarrow\ x\left(x^2-ux+\frac{\Lambda_0^4}{4}\right). \tag{SW14.11}

The surviving curve degenerates at u=±Λ02u=\pm\Lambda_0^2. It is the pure curve in the second-paper package, (11.7). Its relation to the earlier (x2−Λ04)(x−u)(x^2-\Lambda_0^4)(x-u) curve is a degree-two covering relation, called an isogeny. It changes the period lattice in the way (SW14.3) requires; merely renaming xx would not perform this change.

The controlled low-energy regime is E,∣a∣≪∣m∣E,|a|\ll |m|, away from additional light thresholds. At fixed nonzero Λ1\Lambda_1, sending mm to infinity also changes Λ0\Lambda_0; it does not compare one fixed pure theory. The simultaneous limit above does.

A double branch point obeys F=∂xF=0F=\partial_xF=0. Eliminate uu using u=(3x2+mΛ13/4)/(2x)u=(3x^2+m\Lambda_1^3/4)/(2x). The remaining equation is 32x3−8mΛ13x+Λ16=032x^3-8m\Lambda_1^3x+\Lambda_1^6=0. Equivalently, the cubic discriminant is

disc⁡xF=−Λ1616[u3−m2u2−98mΛ13u+m3Λ13+27256Λ16].(SW14.12)\operatorname{disc}_xF=-\frac{\Lambda_1^6}{16} \left[ u^3-m^2u^2-\frac98m\Lambda_1^3u +m^3\Lambda_1^3+\frac{27}{256}\Lambda_1^6 \right]. \tag{SW14.12}

To expand its finite roots, substitute (SW14.10), divide the bracket by −m2-m^2, and solve near u=±Λ02u=\pm\Lambda_0^2. For positive m,Λ0m,\Lambda_0,

u±=±Λ02−Λ0416m2+O ⁣(Λ06m4),uq=m2+Λ048m2+O ⁣(Λ06m4).(SW14.13)u_\pm=\pm\Lambda_0^2-\frac{\Lambda_0^4}{16m^2} +O\!\left(\frac{\Lambda_0^6}{m^4}\right), \qquad u_{\rm q}=m^2+\frac{\Lambda_0^4}{8m^2} +O\!\left(\frac{\Lambda_0^6}{m^4}\right). \tag{SW14.13}

For example, the finite-root equation is u2−Λ04−(u3−9Λ04u/8)/m2+O(m−4)=0u^2-\Lambda_0^4-(u^3-9\Lambda_0^4u/8)/m^2+O(m^{-4})=0. Writing u=±Λ02+c/m2u=\pm\Lambda_0^2+c/m^2 yields c=−Λ04/16c=-\Lambda_0^4/16. The sum of the three roots is m2m^2, which fixes the displayed heavy-root correction.

In units Λ0=1\Lambda_0=1, direct double-root solutions give:

mmu−u_-u+u_+uqu_{\rm q}
4−1.003876200.9960627516.00781345
8−1.000974660.9990215264.00195314
16−1.000244020.99975574256.00048828

The distant singularity approaches the elementary condition u=m2u=m^2; the two finite ones recover the pure theory. This identification is controlled at large mass. Continuing labels to small mass requires periods and paths, not a permanent declaration that one root is always “the quark.”

A separate period check is more demanding than checking the polynomial limit. At u=3u=3, let e1<e2<e3e_1<e_2<e_3 be the three real roots of FF. Orient the electric cycle to go from e1e_1 to e2e_2 on the sheet with positive yy, then return on the other sheet. Substituting x=e1+(e2−e1)sin⁡2θx=e_1+(e_2-e_1)\sin^2\theta removes the endpoint square roots and gives

dAdu=22π∫0π/2dθe3−e1−(e2−e1)sin⁡2θ.\frac{dA}{du}=\frac{\sqrt2}{2\pi} \int_0^{\pi/2} \frac{d\theta}{\sqrt{e_3-e_1-(e_2-e_1)\sin^2\theta}}.

This gives dA/du=0.2086486387dA/du=0.2086486387 for m=4m=4 and 0.20865620590.2086562059 for m=16m=16, approaching 0.20865671040.2086567104. The limit equals one half of the earlier first-paper da/duda/du. Doubling mm reduces the difference by approximately four, as the m−2m^{-2} curve correction predicts.

For Nf=4N_f=4, b=0b=0. At zero masses the theory has an exactly marginal gauge coupling: it is a family of N=2 superconformal theories, rather than an asymptotically free theory specified by a generated scale. A generic nonzero uu is still a Coulomb vacuum that introduces a scale; it is not the conformally invariant vacuum at the origin. The flavor Lie algebra is so(8)\mathfrak{so}(8). Tachikawa, section 9.1

One must not insert b=0b=0 into (SW14.9) and read Λ0\Lambda^0 as a generated scale. A mass restores dimensional running below its threshold. The numerical matching coefficient depends on the chosen coupling coordinate and scale calibration. For example, the second paper’s weak-coupling limit uses Λ3=64qSW1/2m4\Lambda_3=64q_{\rm SW}^{1/2}m_4, with qSW=e2πiτSWq_{\rm SW}=e^{2\pi i\tau_{\rm SW}}. Here τSW\tau_{\rm SW} is the conformal curve’s period-ratio parameter in the second-paper normalization. Hold the product 64qSW1/2m4=Λ364q_{\rm SW}^{1/2}m_4=\Lambda_3 fixed as m4→∞m_4\to\infty, qSW→0q_{\rm SW}\to0. This is its specific (16.39), not a license to set every threshold coefficient to one in every source.

Four fundamental hypers are not an adjoint hyper. Their gauge representation and interactions differ, so a vanishing beta function does not establish N=4 supersymmetry. The adjoint-matter comparison is a separate calculation.

1. Continue around an elementary threshold

Section titled “1. Continue around an elementary threshold”

Near A0=m/2A_0=m/\sqrt2, take the sourced local behavior B=c−i(A−A0)log⁡[(A−A0)/μref]/(2π)+regularB=c-i(A-A_0)\log[(A-A_0)/\mu_{\rm ref}]/(2\pi)+\text{regular}, where μref≠0\mu_{\rm ref}\ne0 makes the logarithm dimensionless. Continue once counterclockwise. Find the transformation of (m/2,B,A)T(m/\sqrt2,B,A)^T, and the compensating transformation of the charge row (S,p,q)(S,p,q). Check an arbitrary central charge and identify the locally vanishing electric-flavor combination.

Hint 1

The logarithm acquires 2πi2\pi i. The mass is a fixed parameter and does not acquire this shift.

Hint 2

Write the affine transformation as a three-by-three matrix. Transform the charge row by its inverse.

Solution

The shift is B′=B+A−m/2B'=B+A-m/\sqrt2, while A′=AA'=A and m′=mm'=m. Thus

Πf′=(100−111001)Πf,(S′,p′,q′)=(S+p,p,q−p).\Pi_f'= \begin{pmatrix}1&0&0\\-1&1&1\\0&0&1\end{pmatrix}\Pi_f, \qquad (S',p',q')=(S+p,p,q-p).

Indeed,

(S+p)m2+p(B+A−m2)+(q−p)A=Sm2+pB+qA.(S+p)\frac m{\sqrt2}+p\left(B+A-\frac m{\sqrt2}\right)+(q-p)A =S\frac m{\sqrt2}+pB+qA.

The state p=0,q=−1,S=1p=0,q=-1,S=1, or its CPT conjugate, has Z=−A+m/2Z=-A+m/\sqrt2 and vanishes at A0A_0. The matrix records analytic continuation and charge-coordinate compensation; it does not prove that every transformed charge is a stable state. The local logarithm and its mass shift are Seiberg–Witten (6.1)–(6.4).

Use the two-flavor source curve

y2=(x2−Λ2464)(x−u)+m1m2Λ224x−(m12+m22)Λ2464.y^2=\left(x^2-\frac{\Lambda_2^4}{64}\right)(x-u) +\frac{m_1m_2\Lambda_2^2}{4}x -\frac{(m_1^2+m_2^2)\Lambda_2^4}{64}.

First take m2→∞m_2\to\infty at fixed Λ13=m2Λ22\Lambda_1^3=m_2\Lambda_2^2. Then remove m1m_1. Compare with reversing the order and with taking both large while fixing Λ04=m1m2Λ22\Lambda_0^4=m_1m_2\Lambda_2^2. What information would be lost by replacing either complex mass by its modulus?

Hint 1

In the first limit, the term m22Λ24m_2^2\Lambda_2^4 stays finite, even though Λ2\Lambda_2 tends to zero.

Hint 2

In the simultaneous limit express every correction using 1/m11/m_1 and 1/m21/m_2. No assumption that the two masses are equal is needed.

Solution

The first limit gives y2=x2(x−u)+m1Λ13x/4−Λ16/64y^2=x^2(x-u)+m_1\Lambda_1^3x/4-\Lambda_1^6/64, exactly (SW14.5) with mass m1m_1. The next limit fixes Λ04=m1Λ13=m1m2Λ22\Lambda_0^4=m_1\Lambda_1^3=m_1m_2\Lambda_2^2. Interchanging the labels yields the same relation.

In the simultaneous limit the right side is

x(x2−ux+Λ044)−Λ08(x−u)64m12m22−Λ0864(1m12+1m22).x\left(x^2-ux+\frac{\Lambda_0^4}{4}\right) -\frac{\Lambda_0^8(x-u)}{64m_1^2m_2^2} -\frac{\Lambda_0^8}{64}\left(\frac1{m_1^2}+\frac1{m_2^2}\right).

Both corrections vanish whenever both masses become large at fixed low-energy scale. Each term has mass dimension six. Their phases, and the phase of the surviving scale, depend on m1m2m_1m_2; absolute-value replacement would erase that holomorphic threshold information. The given curve and calibration are Seiberg–Witten (13.4)–(13.6).

3. Separate a conformal theory from its vacuum

Section titled “3. Separate a conformal theory from its vacuum”

Consider the massless four-flavor theory. Does b=0b=0 mean its generic Coulomb vacuum is conformally invariant, that it has sixteen supercharges, or that adding one nonzero mass preserves conformal invariance? Explain each answer and identify what the mass preserves.

Hint 1

Distinguish a dimensionless coupling, a dimensionful expectation value, and a dimensionful parameter in the action.

Hint 2

A fundamental hypermultiplet and an adjoint hypermultiplet are different representations even when their contributions can cancel the same beta coefficient.

Solution

The massless theory has a dimensionless exactly marginal coupling. At u=0u=0 its vacuum can preserve conformal symmetry. Choosing u≠0u\ne0, with [u]=2[u]=2, introduces a scale through the state and spontaneously breaks that symmetry; this does not create a running coupling in the underlying massless action.

The theory has eight real supercharges. Four doublet hypers are not one adjoint hyper, and cancellation of a beta coefficient does not supply extra supersymmetry transformations.

A fixed nonzero mass is a relevant dimensionful deformation of the action. It breaks conformal invariance explicitly while preserving N=2 supersymmetry. Below a heavy mass the remaining three-flavor theory has b=1b=1, so its matched scale can be proportional to that mass times a dimensionless function of the original coupling. Generic Coulomb vacua continue to preserve all eight Poincaré supercharges.

The useful checkpoint is to reproduce one quark mass, one flavor residue and the fixed-Λ0\Lambda_0 decoupling limit in a single convention. The adjoint-hypermultiplet lesson introduces the new field content and mass analysis needed to reach N=4 and its N=2-star deformation.

Use the second-paper companion to return to the original convention note and reconstruct the degree-two curve map, including the differential and its cycle normalization.