Skip to content

Build a Seiberg-duality dictionary

The preceding lesson described a strongly coupled gauge theory using mesons and baryons. Sometimes those composites alone do not provide the useful infrared description: a second gauge theory does. Its gauge group can even have a different rank.

We will construct a concrete dictionary between an electric SU(3)SU(3) theory with five flavors and a magnetic SU(2)SU(2) theory. The task is to identify fields, interactions, and gauge-invariant operators precisely enough that the proposed equivalence can be tested.

Both theories live in flat four-dimensional Lorentzian spacetime and have N=1\mathcal N=1 supersymmetry: four real supercharges, all manifest in N=1\mathcal N=1 superspace. There are no adjoint chiral multiplets. Keep the ordinary trace convention Tr⁡(tAtB)=δAB/2\operatorname{Tr}(t^At^B)=\delta^{AB}/2.

The electric theory has gauge group SU(3)SU(3), rank two, with five fundamental chirals QiaQ_i^a and five independent antifundamentals Q~a j\widetilde Q^{\,j}_a. Here a=1,2,3a=1,2,3 and i,j=1,…,5i,j=1,\ldots,5. Its massless tree superpotential vanishes.

The proposed magnetic theory has gauge group

SU(Nf−Nc)=SU(2),SU(N_f-N_c)=SU(2),

of rank one. It contains five fundamental chirals qiαq^{i\alpha}, five independent antifundamentals q~jα\widetilde q_{j\alpha}, and twenty-five gauge-singlet chirals MjiM^j{}_i. The magnetic color index is α=1,2\alpha=1,2. Each entry of MM is a field; “singlet” means a singlet under magnetic color, not under flavor.

Seiberg duality identifies the long-distance quantum physics near the massless symmetric vacuum, with operators and sources appropriately mapped. This example has an interacting infrared limit. The magnetic gauge field is part of another description of that limit; it is not an extra microscopic field added to the electric Lagrangian. Different gauge redundancies and different numbers of elementary fields can describe the same physical operators. Seiberg, section 3

The two descriptions need not both be weakly coupled. Their gauge beta-function coefficients are 3(3)−5=43(3)-5=4 and 3(2)−5=13(2)-5=1: both gauge sectors are asymptotically free, rather than free in the deep infrared. These coefficients alone do not establish the common interacting limit or control its coupling at these small ranks. Nor does duality assert equality of the two microscopic actions at all energies.

Write the unrescaled electric composite with a different symbol:

Mji=Q~a jQia,[M]=2.\mathcal M^j{}_i=\widetilde Q^{\,j}_aQ_i^a, \qquad [\mathcal M]=2 .

As before, its row is jj and its column is ii. The elementary magnetic field has ultraviolet engineering dimension [M]=1[M]=1. Introduce a nonzero complex matching scale μ∗\mu_* of dimension one and write the operator dictionary

Mji ⟷ μ∗Mji.(Q09.1)\mathcal M^j{}_i\ \longleftrightarrow\ \mu_* M^j{}_i. \tag{Q09.1}

The arrow identifies renormalized operators flowing to the same infrared operator. It is not an identity between numerical elementary fields in the two path integrals. Engineering dimensions at their respective ultraviolet descriptions need not coincide before inserting this conversion factor. μ∗\mu_* fixes an operator normalization; it is not an additional flavor mass.

The magnetic superpotential is

Wm=h∑i,j,αMjiqiαq~jα,h≠0.(Q09.2)W_{\mathrm m} =h\sum_{i,j,\alpha}M^j{}_i q^{i\alpha}\widetilde q_{j\alpha}, \qquad h\ne0 . \tag{Q09.2}

Here hh is a dimensionless holomorphic coupling. It is not determined numerically by the charge table below. A nonzero interaction is part of the proposed dual dynamics.

Intriligator–Seiberg write the singlet in electric-composite units and use W=Mqq~/μW=\mathcal M q\widetilde q/\mu. To translate their formulas while retaining our explicit hh, define

μ=μ∗h,Wm=1μ∑i,j,αMjiqiαq~jα.(Q09.3)\mu=\frac{\mu_*}{h}, \qquad W_{\mathrm m}=\frac1\mu\sum_{i,j,\alpha} \mathcal M^j{}_i q^{i\alpha}\widetilde q_{j\alpha}. \tag{Q09.3}

Their holomorphic scale relation specializes to

Λe 4Λm=μ5=(μ∗h)5.(Q09.4)\Lambda_{\mathrm e}^{\,4}\Lambda_{\mathrm m} =\mu^5 =\left(\frac{\mu_*}{h}\right)^5. \tag{Q09.4}

The general source phase is (−1)Nf−Nc(-1)^{N_f-N_c}, which is +1+1 here. The exponents 44 and 11 are the two beta-function coefficients. Both sides have dimension five; phases matter as well as magnitudes. This is a sourced matching convention, not an equation obtained by equating two canonical running couplings. Intriligator–Seiberg, (5.5)–(5.6)

A rescaling of the elementary singlet changes μ∗\mu_* and hh together. Setting h=1h=1 by a holomorphic field redefinition need not leave its kinetic term canonical. The unknown wavefunction factors must be included when discussing physical couplings or masses.

Use the electric flavor convention of the SQCD lesson: QQ is a fundamental of SU(5)LSU(5)_L, while Q~\widetilde Q is an antifundamental of SU(5)RSU(5)_R. To make (Q09.2) invariant, qq must have the conjugate left representation and q~\widetilde q the conjugate right representation:

Chiral fieldGauge representationLeft flavorRight flavorBaryon chargeScalar R-charge
Electric QQ3\mathbf35\mathbf51\mathbf1112/52/5
Electric Q~\widetilde Q3‾\overline{\mathbf3}1\mathbf15‾\overline{\mathbf5}−1-12/52/5
Magnetic qq2\mathbf25‾\overline{\mathbf5}1\mathbf13/23/23/53/5
Magnetic q~\widetilde q2‾\overline{\mathbf2}1\mathbf15\mathbf5−3/2-3/23/53/5
Magnetic MM1\mathbf15\mathbf55‾\overline{\mathbf5}004/54/5

The fractional baryon charges will follow from the baryon map. First derive the R column. A chiral scalar of R-charge rr has a Weyl partner of charge r−1r-1; each gaugino has charge one. Gauge consistency therefore requires

kSU(3)2R=3+5(re−1)=0,re=25,kSU(2)2R=2+5(rm−1)=0,rm=35.(Q09.5)\begin{aligned} k_{SU(3)^2R}&=3+5(r_{\mathrm e}-1)=0, &r_{\mathrm e}&=\frac25,\\ k_{SU(2)^2R}&=2+5(r_{\mathrm m}-1)=0, &r_{\mathrm m}&=\frac35 . \end{aligned} \tag{Q09.5}

Each flavor pair contributes two fundamental indices T(fund)=1/2T(\mathbf{fund})=1/2, explaining the factor five. Gauge-singlet mesons contribute nothing to the second equation. The electric composite has R-charge 2re=4/52r_{\mathrm e}=4/5, fixing the singlet charge when μ∗\mu_* is neutral. The interaction then has

R(Wm)=45+35+35=2.R(W_{\mathrm m})=\frac45+\frac35+\frac35=2.

The matching scales and hh are neutral under this anomaly-free R assignment. Gauge invariance of an R current is different from matching its global anomalies between descriptions; that further test comes next.

We have chosen the assignment symmetric between each quark and antiquark. Mixing with baryon number remains possible: R↦R+sBR\mapsto R+sB gives electric quark charges 2/5±s2/5\pm s and magnetic charges 3/5±3s/23/5\pm3s/2. The mixed gauge anomalies and the superpotential still allow this. Identifying the superconformal R-symmetry, and using it to determine infrared scaling dimensions, requires a further argument. We have not made that identification here.

Although magnetic color is SU(2)SU(2) and its fundamental is pseudoreal, the whole theory does not acquire the SU(10)SU(10) symmetry of ten doublets with only gauge interactions. The twenty-five singlets and their nonzero superpotential select the displayed five-plus-five flavor split. Seiberg, (3.1)–(3.3)

An electric baryon uses three colors:

Bijk=εabcQiaQjbQkc,B~ijk=εabcQ~a iQ~b jQ~c k.B_{ijk}=\varepsilon_{abc}Q_i^aQ_j^bQ_k^c, \qquad \widetilde B^{ijk}= \varepsilon^{abc}\widetilde Q^{\,i}_a \widetilde Q^{\,j}_b\widetilde Q^{\,k}_c .

For increasing flavor indices these are determinants, with no factorial. Each side has (53)=10\binom53=10 independent components. A magnetic baryon instead uses two colors:

blm=εαβqlαqmβ,b~lm=εαβq~lαq~mβ,ε12=ε12=1.b^{lm}=\varepsilon_{\alpha\beta}q^{l\alpha}q^{m\beta}, \qquad \widetilde b_{lm} =\varepsilon^{\alpha\beta}\widetilde q_{l\alpha} \widetilde q_{m\beta}, \qquad \varepsilon_{12}=\varepsilon^{12}=1.

These epsilons orient color determinants; they are not the Lorentz spinor raising/lowering tensors. Again there are (52)=10\binom52=10 components. With flavor orientation ε12345=1\varepsilon_{12345}=1, the map is

Bijk ⟷ κ2εijklmblm,B~ijk ⟷ κ~2εijklmb~lm.(Q09.6)B_{ijk}\ \longleftrightarrow\ \frac{\kappa}{2}\varepsilon_{ijklm}b^{lm}, \qquad \widetilde B^{ijk}\ \longleftrightarrow\ \frac{\widetilde\kappa}{2}\varepsilon^{ijklm}\widetilde b_{lm}. \tag{Q09.6}

The factor 1/21/2 compensates the sum over both orders of l,ml,m. In particular B123↔κb45B_{123}\leftrightarrow\kappa b^{45}. The flavor epsilon converts the two conjugate-flavor indices into three electric-flavor indices; equality of component counts is not by itself the reason the map transforms correctly.

Electric baryons have baryon charge three. Thus 2B(q)=32B(q)=3, explaining B(q)=3/2B(q)=3/2; the tilde charges follow similarly. The R-charges also agree: 3(2/5)=2(3/5)=6/53(2/5)=2(3/5)=6/5. The engineering dimensions do not: [B]=3[B]=3, [b]=2[b]=2. Consequently [κ]=[κ~]=1[\kappa]=[\widetilde\kappa]=1, while both coefficients are baryon- and R-neutral.

These checks do not fix their numerical normalization or phase. In the holomorphic determinant convention compatible with (Q09.4), the sourced product is

κκ~=−Λe 4μ2.(Q09.7)\kappa\widetilde\kappa =-\frac{\Lambda_{\mathrm e}^{\,4}}{\mu^2}. \tag{Q09.7}

A convenient local convention sets κ=κ~\kappa=\widetilde\kappa and chooses a square root of the right side. Rephasing baryons changes the displayed dictionary; the root choice is not a physical extra vacuum. This implements Intriligator–Seiberg, (5.10) with explicitly normalized component minors.

A worked check fixes the baryon-product sign

Section titled “A worked check fixes the baryon-product sign”

Consider an electric vacuum patch with

M=diag⁡(x1,x2,x3,0,0),x1x2x3≠0.\mathcal M=\operatorname{diag}(x_1,x_2,x_3,0,0), \qquad x_1x_2x_3\ne0 .

The first three flavors can span color. Their ordinary minor identity gives B123B~123=x1x2x3B_{123}\widetilde B^{123}=x_1x_2x_3. In the magnetic theory these three meson entries give holomorphic masses xa/μx_a/\mu to three magnetic flavor pairs. Removing them leaves the two-flavor SU(2)SU(2) theory already studied. Its scale is

Llow=x1x2x3μ3Λm.\mathcal L_{\mathrm{low}} =\frac{x_1x_2x_3}{\mu^3}\Lambda_{\mathrm m}.

Begin where those magnetic thresholds are large enough for the usual scale matching, then continue the holomorphic relation. This does not require both descriptions to have canonical weakly coupled metrics at the same point.

Let NN be the two-by-two meson made from the remaining magnetic flavors 4,54,5. The light singlet equations set N=0N=0, while their magnetic quantum constraint gives

det⁡N−b45b~45=Llow⟹b45b~45=−Llow.\det N-b^{45}\widetilde b_{45}=\mathcal L_{\mathrm{low}} \quad\Longrightarrow\quad b^{45}\widetilde b_{45}=-\mathcal L_{\mathrm{low}}.

This is a consistent low-energy vacuum: introduce a multiplier for that constraint, set it and the light singlet block to zero, and choose the displayed nonzero baryon product. Every remaining F equation then vanishes. As in the preceding lesson, these are quantum composite coordinates, not numerical quark matrices required to violate a classical determinant identity.

Applying (Q09.6) and requiring the electric minor identity yields

κκ~=−μ3Λm=−Λe 4μ2,\kappa\widetilde\kappa =-\frac{\mu^3}{\Lambda_{\mathrm m}} =-\frac{\Lambda_{\mathrm e}^{\,4}}{\mu^2},

which is (Q09.7). The minus sign comes from the quantum constraint, not from an arbitrary claim that operators with matching charges have equal coefficients. This check is the specialization of Intriligator–Seiberg, (5.19)–(5.20).

The gauge-invariant magnetic product Nij=∑αqiαq~jαN^i{}_j=\sum_\alpha q^{i\alpha}\widetilde q_{j\alpha} has the flavor representation conjugate to the electric meson. It is not the image of M\mathcal M: that image is the elementary singlet μ∗M\mu_*M.

Varying the full singlet gives

∂Wm∂Mji=hNij.(Q09.8)\frac{\partial W_{\mathrm m}}{\partial M^j{}_i}=hN^i{}_j . \tag{Q09.8}

The singlet equation of motion makes this magnetic product a supersymmetry descendant, hence zero in the chiral ring when no source is present. In a Wilsonian description its F equation is also a necessary vacuum condition. The remaining equations are ∑jMjiq~jα=0\sum_jM^j{}_i\widetilde q_{j\alpha}=0 and ∑iMjiqiα=0\sum_iM^j{}_iq^{i\alpha}=0. Thus the interaction removes an unwanted independent chiral operator. Setting h=0h=0 changes the proposed dual theory.

One must still include quantum dynamics when comparing entire vacuum spaces. Classically the magnetic equations permit q=q~=0q=\widetilde q=0 with an arbitrary singlet matrix, whereas the electric meson has rank at most three. The magnetic dynamics of the remaining flavors restore the required restrictions; the rank-three example above already uses their quantum constraint. A field list and classical F equations alone are not the whole duality. Intriligator–Seiberg, section 5.5

1. Check a baryon component and a fractional charge

Section titled “1. Check a baryon component and a fractional charge”

Find the magnetic image of B124B_{124}, including its sign, and check its baryon and R-charges. Under a baryon rotation of angle 2π2\pi, what happens to the magnetic quarks? Does this contradict the operator dictionary?

Hint 1

The missing flavors are 3,53,5. Compare the ordering 1,2,4,3,51,2,4,3,5 with the chosen orientation.

Hint 2

A magnetic quark has charge 3/23/2, but is gauge-variant. The center of SU(2)SU(2) contains −1-\mathbf1.

Solution

The relevant permutation has one interchange, so

B124⟷−κb35.B_{124}\longleftrightarrow-\kappa b^{35}.

Both sides have baryon charge 33 and R-charge 6/56/5; the dimension-one coefficient supplies the engineering-dimension difference. Under a 2π2\pi baryon rotation, q↦e3πiq=−qq\mapsto e^{3\pi i}q=-q and q~↦e−3πiq~=−q~\widetilde q\mapsto e^{-3\pi i}\widetilde q=-\widetilde q. This is the magnetic gauge-center transformation. Gauge-invariant operators are unchanged, so fractional charges of the gauge-variant quarks cause no contradiction. This checks that particular finite transformation; it is not a specification of every quotient in the full global symmetry group.

2. Change the elementary meson normalization

Section titled “2. Change the elementary meson normalization”

Set M′=cMM'=cM with a nonzero dimensionless complex constant cc, leaving magnetic quarks fixed. Rewrite the dictionary and superpotential, and determine whether μ\mu in (Q09.3) changes. If the kinetic term has coefficient ZMZ_M, what happens to it? Finally map an electric source JijMjiJ^i{}_j\mathcal M^j{}_i and check that the source interaction is unchanged.

Hint 1

Replace every old MM by M′/cM'/c, including in the operator map.

Hint 2

The source is held fixed while changing field coordinates. Its engineering dimension is one.

Solution

The new parameters are

μ∗′=μ∗c,h′=hc,μ′=μ∗′h′=μ,ZM′=ZM∣c∣2.\mu_*'=\frac{\mu_*}{c},\qquad h'=\frac hc,\qquad \mu'=\frac{\mu_*'}{h'}=\mu,\qquad Z_M'=\frac{Z_M}{|c|^2}.

Thus the holomorphic scale relation and baryon-product coefficient are unchanged. A general holomorphic rescaling does not preserve a specified canonical kinetic coefficient.

The electric source maps to Jijμ∗Mji=Jijμ∗′M′jiJ^i{}_j\mu_*M^j{}_i=J^i{}_j\mu_*'M'^j{}_i. It has dimension three and R-charge two: [J]=1[J]=1, R(J)=6/5R(J)=6/5, while μ∗\mu_* is neutral and R(M)=4/5R(M)=4/5. The R charge of JJ is a spurion assignment; fixing a nonzero source need not preserve the original R symmetry. Forgetting μ∗\mu_* would give both the wrong engineering dimension and a normalization-dependent source map.

3. Remove the interaction and test a candidate vacuum

Section titled “3. Remove the interaction and test a candidate vacuum”

At the level of the magnetic classical action, set M=0M=0 and take only

q4α=(w,0),q~4α=(w,0),w≠0q^{4\alpha}=(w,0),\qquad \widetilde q_{4\alpha}=(w,0),\qquad w\ne0

to be nonzero. Check D-flatness and decide whether the configuration is F-flat for h=0h=0 and for h≠0h\ne0. What does this teach about trying to infer duality from the field content and gauge-anomaly-free charge assignment alone?

Hint 1

The color moment map uses qq†−q~†q~qq^\dagger-\widetilde q^\dagger\widetilde q. The tilde scalar is independently chosen equal here, not generally defined by conjugation.

Hint 2

The singlet whose derivative can be nonzero is M44M^4{}_4.

Solution

Both terms in the moment map are diag⁡(∣w∣2,0)\operatorname{diag}(|w|^2,0), so every SU(2)SU(2) D equation vanishes. If h=0h=0 there is no superpotential and all classical F equations vanish as well.

For h≠0h\ne0,

∂Wm∂M44=hw2≠0.\frac{\partial W_{\mathrm m}}{\partial M^4{}_4}=h w^2\ne0 .

The other superpotential derivatives vanish on the stated configuration, but one nonzero F equation is enough to exclude it as a supersymmetric vacuum of that classical action. With a positive nonsingular singlet kinetic metric its F contribution to the energy is positive; the metric sets the numerical coefficient.

Removing the interaction changes the equations and leaves an additional magnetic meson operator unconstrained. The same field list and the charge assignment used in (Q09.5) do not by themselves establish the proposed infrared equivalence. This classical diagnostic is not a claim that classical equations determine either theory’s complete quantum vacuum space.

We now have a dictionary with specified fields, interactions, charges, operator normalizations and scale phases. Continue with Check a duality with anomalies and a mass deformation to compare the global anomalies and follow an electric flavor mass into magnetic Higgsing. These tests probe the dictionary in different ways, without turning any single check into a proof of the entire duality.